Zend Preparation | PHP Quiz (Learning Mode)

PHP Basics Learning Mode

Qusetions Index 30/260

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Consider the following code:

<?php
    $a;
    for($a=1;$a<=100;$a++)
    {
    if($a==50)
    {
        continue;
    }
    print($a);
    }
?>

What will be the output of the program?

A series from 1 to 100 will be printed. The number 50 will not be printed.

A series from 1 to 50 will be printed.

A series from 51 to 100 will be printed.

A series from 1 to 100 will be printed.

Explanation: In the given program, the continue statement forces the program to jump to a++. The value is incremented by one, and hence 51 is printed and 50 is skipped.

What is the increment operator?
The increment operator is a unary operator. Its sign is ++. It displays two different behaviors depending on the position of the operator. The two behaviors are as follows:

- x++
- ++x

Both of the above statements mean x=x+1. But when these are assigned to a variable, the meaning is changed. Let us see this in the following example:

Suppose the value of x=10, then in the statement b=++x, the value of variables x and b will be 11. It is so because b=++x contains two statements:

- b=x
- x=x+1

Since the statement executes from left to right and the ++ operator has more priority than the = operator, first x will be incremented to one, and then its value will be assigned to b.

In case of the statement b=x++, the value of b will be 10 and the value of x will be 11 because b=x++ contains two statements.

- b=x
- x=x+1

In this case, when the statement executes from left to right, it comes in contact with the variable x. The value of x is assigned to b and x is incremented to 1.