Zend Preparation | PHP Quiz (Learning Mode)

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Is the following PHP code valid or will it generate an error, warning or notice?

<?php
    error_reporting(E_ALL | E_STRICT);

    $newArray[E_STRICT] = 'foo';
?>

Yes, it's completely valid

Invalid, you must define $newArray by calling array() first

Invalid, E_STRICT is not defined

Invalid, you cannot use a constant as an array key